Algebra 2
posted by Trisan .
How much pure acid must be added to 6 milliliters of a 5% acid solution to produce a 40% acid solution? Please Show All Work!

c1 v1 + c2 v2 = c3 (v1+v2)
5 x 6 + 100(Pure acid) x v2 =
40(6+v2)
30 + 100v2 = 240 + 40v2
60v2 = 210
v2 = 21/6 = 7/2 =
3.5ml is the answer
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