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How many grams of Na2CO3 can be produced from 2.715 g NaHCO3?
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How many grams of Na2CO3 can be produced from 2.715 g NaHCO3?
Top answer:
Rose, all of these stoichiometry problems are worked the same way. Step 1. Write the balanced
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0.7g of an unknown mixture of NaHCO3 and Na2CO3 is mixed with 3mL of 12M HCl.what is the mass of NaHCO3 and Na2CO3 in the
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Let X = mass Na2CO3 then Y = mass NaHCO3 ========================================= X + Y = 0.7g
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Balance this equation.
NaHCO3(s) + heat ----> Na2CO3(s) + H2O(l) + CO2(g). i balanced it & got: 2NaHCO3(s)+ heat -->Na2CO3(s)+
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would the answer be 14 moles of CO2?
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1) Which solution will have the lowest OH-
A) Na2CO3 B) NaHCO3 C) NaCl D) NaHSO4 E) NH4Cl 2) Which solution will be the strongest
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1) Which solution will have the lowest OH- A) Na2CO3 B) NaHCO3 C) NaCl D) NaHSO4 E) NH4Cl The lowest
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Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s).
2NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g)
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Did you make typo? If Kp is at 160 C then it will be different at 100 C. Assuming you mean Ptotal at
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You weigh out 10.000 g of a mixture of NaHCO3 and Na2CO3 and add an excess of HCl. After the reaction is over, you evaporate off
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See your post above.
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You weigh out 10.000 g of a mixture of NaHCO3 and Na2CO3 and add an excess of HCl. After the reaction is over, you evaporate off
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NaHCO3 + HCl ==> NaCl + H2O + CO2 Na2CO3 + 2HCl --> 2NaCl + H2O + CO2 Let X = mass NaHCO3 and Y =
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for a lab it says prepare a 300 ml of .2% sodium bicarbonate solution. I am trying to find how many grams of NaHCO3 i need. so i
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Density=mass/volume, solve for mass Density of NaHCO3=2.20 g/mL
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use the Henderson-Hasselbalch equation to calculate the pH of a buffer solution prepared by mixing equal volumes of 0.20 M
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pH = pKa + log(base)/(acid) pH = 10.25 + log (0.05/0.1)=? 10.4 = 10.25 + log b/a b/a = ? = approx =
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Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s).
2NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) Kp
Top answer:
Kp = 0.23 = pCO2*pH2O pCO2 = pH2O p = sqrt(0.23) = ? pCO2 + pH2PO = ?
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