If a car accelerates from rest at a constant 5.5m/s^2, how long will be required to reach 28m/s?
t=(v-u)/a
t= (28m/s- 0m/s)/5.5m/s^2
= (28m/s)/5.5m/s^2
t= 5.09s
ok so you use the First kinematic relation:
V=u+at
where v is the final velocity
u is the initial velocity
a is acceleration
t is time taken
So, for this question
v= 28m/s
u= 0 m/s (because car was at rest)
a= 5.5m/s^2
t= what you need to find out
Solve for t and substitute the values
t= (v-u)/a
Well, if I were that car trying to reach 28 m/s, I would have to put on my driving cap and say, "Buckle up, folks, because this is going to be a wild ride!" Now, let's crunch those numbers.
To find the time it takes for the car to reach 28 m/s with an acceleration of 5.5 m/sĀ², we can use the equation:
v = u + at,
where v is the final velocity, u is the initial velocity (which is 0 m/s since the car starts from rest), a is the acceleration, and t is the time we're trying to find.
Plugging in the values we know:
28 = 0 + (5.5)t.
Now, if I were a mathematician clown, I would perform a little circus trick known as solving for t. Dividing both sides of the equation by 5.5, we get:
t = 28/5.5.
And if we simplify that, we find that t is approximately equal to 5.09 seconds.
Voila! In approximately 5.09 seconds, that car should reach a speed of 28 m/s. Just make sure to hold on tight and enjoy the ride!
To find the time required for the car to reach 28 m/s from rest given an acceleration of 5.5 m/s^2, you can use the kinematic equation:
š£ = š¢ + šš”,
where:
- š£ is the final velocity (28 m/s),
- š¢ is the initial velocity (0 m/s, since the car starts from rest),
- š is the acceleration (5.5 m/s^2),
- š” is the time we want to find.
Rearranging the equation, we have:
š” = (š£ - š¢) / š.
Substituting the known values into the equation:
š” = (28 m/s - 0 m/s) / 5.5 m/s^2.
Simplifying:
š” = 28 m/s / 5.5 m/s^2.
Dividing the units and calculating the result:
š” ā 5.09 seconds.
Therefore, it will take approximately 5.09 seconds for the car to reach 28 m/s.