The problem is
(14ac)-a^2-2ac+b^2)
I need to subtract by removing a factor of 1 when possible
the answer that I got is
-a^2+16ac+b^2
can anyone tell me if this is right and if not can you help me solve
You wrote : (14ac)-a^2-2ac+b^2)
I noticed that you have one right bracket but two left brackets, so that indicates a typo error. (Syntax error in "old computer programming" language)
You probably meant:
(14ac) - (a^2-2ac+b^2)
= 14ac - a^2 + 2ac - b^2
= 16ac - a^2 - b^2
You almost had that, except for the -b^2
Thank you
To solve the problem, you need to simplify the expression by subtracting a common factor whenever possible. Let's go step by step together:
Starting with the expression:
(14ac - a^2 - 2ac + b^2)
First, let's combine the like terms:
(14ac - 2ac - a^2 + b^2)
Next, let's simplify the expression by combining the "ac" terms and grouping the "a^2" and "b^2" terms:
(12ac - a^2 + b^2)
Now, let's look for a common factor that we can subtract. In this case, we cannot remove a common factor since none of the terms have a common factor.
Therefore, the simplified expression is:
(12ac - a^2 + b^2)
The answer you got, (-a^2 + 16ac + b^2), is not correct. The correct simplified expression is (12ac - a^2 + b^2).
Remember, when subtracting by removing a factor of 1, you need to look for terms that have a common factor that can be factored out. In this case, there is no common factor to remove.