Find the value of the polynomial when x = 4. 4x3 - 3x2 - 3x + 2
To indicate a power online, x^3 = x cubed. Substitute the value, 4, for x.
4 (4^3) - 3 (4^2) - 3(4) + 2 = ?
coefficients of the given polynomial: -2x3 – 9x2 + 5x + 1
To find the value of the polynomial 4x^3 - 3x^2 - 3x + 2 when x = 4, we can substitute the value of x into the polynomial expression and evaluate it.
Substituting x = 4 into the polynomial, we have:
4(4)^3 - 3(4)^2 - 3(4) + 2
To simplify the expression, we'll perform the necessary calculations using the order of operations (PEMDAS/BODMAS).
First, we'll calculate the exponents:
4^3 = 4 * 4 * 4 = 64
(4)^2 = 4 * 4 = 16
Now, substituting the values, we have:
4(64) - 3(16) - 3(4) + 2
Next, we'll calculate the multiplications:
4 * 64 = 256
3 * 16 = 48
3 * 4 = 12
Now our expression becomes:
256 - 48 - 12 + 2
Next, we'll perform the subtractions and addition:
256 - 48 = 208
208 - 12 = 196
196 + 2 = 198
Therefore, the value of the polynomial 4x^3 - 3x^2 - 3x + 2 when x = 4 is 198.