posted by Anonymous .
A chair of weight 85.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 44.0 N directed at an angle of 42.0 degrees below the horizontal and the chair slides along the floor.
Using Newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.
Resolve the force F=44N into the vertical component Fsin(θ), and the horizontal component Fcos(θ).
Since the angle &theta is below the horizontal, the vertical components tends to lift the chair. So the vertical reaction equals weight-vertical component.