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Honors Chemistry

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Can someone check my work please? Thanks :))

2. Write the formulas for the compounds formed between the following:

g. Cu+2 and NO3- (the +2 and - are superscripts, while the 3 is a subscript)

===> I got Cu(NO3)2.

h. NH4 and SO4(2-) (the two 4's are subscripts, and the (2-) is a superscript)

===> I got (NH4)2(SO4).

  • Honors Chemistry -

    If I understand correctly, then I would write no reaction for both. If Cu^+2 ion and NO3^- ion are put into the same beaker, then the solution will just have the two ions floating around. They will not interact. You may be studying about solubility, gases, and that type of thing. Generally, there are three reasons why a reaction will proceed (plus oxidation reduction reactions but that's another topic).
    a. A precipitate (insoluble material) is formed.
    b. a gas is formed.
    c. a slightly ionized substance is formed.

    Applying those to the two reactions you have, we know they are not gases, they are ionized, and Cu(NO3)2 is soluble, so, no reaction.
    Here is a simplified table of solubilities.
    http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html

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