An object travels in a circular path of 5.0 meters at a uniform speed of 5. m/s. What is the magnitude of the object's acceleration?
I do not know what formula I am suppose to use!
a= v^2/r
To find the magnitude of the object's acceleration, you can use the formula for centripetal acceleration. Centripetal acceleration is the acceleration of an object moving in a circular path, and it is always directed towards the center of the circle.
The formula for centripetal acceleration is given by:
a = v^2 / r,
where:
- a is the centripetal acceleration,
- v is the velocity or speed of the object, and
- r is the radius of the circular path.
In this case, the velocity of the object is given as 5.0 m/s, and the radius of the circular path is 5.0 meters.
Substituting the given values into the formula, we get:
a = (5.0 m/s)^2 / 5.0 m
= 25.0 m^2/s^2 / 5.0 m
= 5.0 m/s^2.
Therefore, the magnitude of the object's acceleration is 5.0 m/s^2.