(3x squared-10x)divided by(x-6)=3x+8+48/x-6. but i have no idea how thaproblem was done. pls show me the steps
I assume that you mean:
(3x^2 - 10x)/(x-6) = (3x + 8 + 48)/(x-6)
If so, multiply both sides by x - 6.
3x^2 - 10x = 3x + 56
Subtract 3x from both sides.
3x^2 - 13x = 56
Factor out x to give you:
x(3x -13) = 56
x = 56 or
3x - 13 = 56
3x = 69
x = 23
I hope this helps. Thanks for asking.