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on earth, in the absence of air, the rock in excersise 13 would reach a height of s=24t- 4.9t^2 meters in t seconds. How high would the rock go?


(exercise 13:a rock thrown vertically upward from the surface of the moon at a velocity of 24m/sec reaches aheight of s=24t-0.t^2.

  • math -

    29.388meters
    52 seconds

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