Henry's bus can go just 12 miles on a gallon of gasoline. When he started his vacation, the gas tank of the bus was 5/6 full. Later, when Henry had driven 336 miles, the gauge showed that the tank was still 3/5 full. If his low on gas light will come on when he has 1/15 a tank remaining, how much farther can he go before seeing that light?
So on (5/6-3/5) tank, he can go 336 miles.
How much can he go for (3/5 - 1/15) of a tank?
I would set up a ratio
x/336 = (3/5 - 1/15)/(5/6 - 3/5)
x/336 = (8/15)/(7/30)
x/336 = 16/7
x = 336(16/7) = 768 miles
To determine how much farther Henry can go before seeing the low gas light, we need to calculate the remaining amount of gas in the tank and then convert it into miles. Here's how we can do that:
1. Start by calculating the total capacity of the gas tank. We know that Henry's bus can go 12 miles on a gallon of gasoline and that the tank was 5/6 full originally. So the total capacity of the tank can be found by multiplying the mileage per gallon by the fraction of the tank that was full: 12 miles/gallon * (5/6) = 10 miles.
2. Next, determine the remaining amount of gas in the tank. We are given that the gauge showed the tank was 3/5 full after driving 336 miles. So we can calculate the remaining gas by multiplying the total capacity of the tank by the fraction of the tank that is full: 10 miles * (3/5) = 6 miles.
3. Now, we need to calculate how much farther Henry can go before seeing the low gas light. We know that the low gas light will come on when the remaining gas in the tank is 1/15 of the total capacity. So we can calculate the maximum distance Henry can go by multiplying the remaining gas by the mileage per gallon: 6 miles * 12 miles/gallon = 72 miles.
Therefore, Henry can go a maximum of 72 miles farther before seeing the low gas light.