How much work must you do to push a 13 block of steel across a steel table at a steady speed of 1.3 for 3.7 ? what is the Wnet and P?

To find the work done, we can use the formula:

Work = Force × Distance

Given:
Mass of the block (m) = 13 kg
Velocity (v) = 1.3 m/s
Time (t) = 3.7 s

First, we need to calculate the force required to maintain a steady speed. The force can be found using Newton's second law of motion:

Force = Mass × Acceleration

Since the block is moving at a steady speed, the acceleration can be assumed to be zero. Therefore, the force required is:

Force = Mass × Acceleration = 13 kg × 0 m/s² = 0 N

Since the force is zero, the work done to maintain the steady speed is also zero.

Now, let's calculate the net work (Wnet) and the power (P).

Net work (Wnet) is given by the formula:

Wnet = Change in Kinetic Energy

Since the block is moving at a steady speed, there is no change in kinetic energy. Therefore, the net work done is also zero.

Power (P) is given by the formula:

P = Work / Time

Since the work is zero, the power is also zero.

In summary:
- The work done to push the block across the table at a steady speed is zero.
- The net work (Wnet) is zero.
- The power (P) is zero.

To calculate the work done, we need to use the equation:

Work (W) = Force (F) x Distance (d) x Cosine (θ)

In this case, we know the force (F) required to push the block is equal to its weight, which is given by:

Force (F) = mass (m) x acceleration due to gravity (g)

Given that the mass of the block is 13 kg and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the force:

F = 13 kg x 9.8 m/s² = 127.4 N

The distance (d) traveled by the block is given as 3.7 m. The angle (θ) between the force and the direction of motion is not mentioned, so we assume it to be 0°, indicating a horizontal motion.

Now, we can plug these values into the work equation:

W = 127.4 N x 3.7 m x cos(0°)

Since the cosine of 0° is 1, this simplifies to:

W = 127.4 N x 3.7 m = 471.38 Joules (J)

Therefore, the work done to push the block is approximately 471.38 J.

Now let's calculate the net work (Wnet) and power (P).

Net work (Wnet) refers to the total work done on an object, which in this case is equal to the work done (W) since there are no other forces acting on the block. So, Wnet = W = 471.38 J.

Power (P) is the rate at which work is done. It can be calculated using the equation:

Power (P) = Work (W) / Time (t)

The time (t) in this scenario is given as 3.7 s.

P = 471.38 J / 3.7 s = 127.4 Watts (W)

Therefore, the net work (Wnet) is 471.38 J and the power (P) is 127.4 Watts.