What is the mass of 7.817 × 1023 atoms Ag?

6.02 x 10^23 atoms of Ag have a mass of 107.87 grams.

To find the mass of 7.817 × 10^23 atoms of Ag (Silver), you need to know the molar mass of silver.

1. Look up the atomic mass of silver (Ag) on the periodic table. It is approximately 107.87 g/mol.

2. Now, divide the molar mass by Avogadro's number, which is 6.022 × 10^23 particles/mol. This will give you the mass of one atom.

(107.87 g/mol) ÷ (6.022 × 10^23 atoms/mol) ≈ 1.792 × 10^-22 g/atom

3. Finally, multiply the mass of one atom by the number of atoms given (7.817 × 10^23).

(1.792 × 10^-22 g/atom) × (7.817 × 10^23 atoms) ≈ 1.400 g

Therefore, the mass of 7.817 × 10^23 atoms of Ag is approximately 1.400 grams.