algebra

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Find the value of y so that the line passing through the two points has the given slope?
1. (12,y), (-6,9/7), m= -1/6
_____________

write an equation in slope-intercept form. (then graph the equation).
2. 18y+2x-9=0
3. 3x-4y=-8

  • algebra -

    y=mx+c
    m= -1/6
    y=-(1/6)x+c
    The point (-6,9/7) must be on that line: use it to find c by plugging in x and y like
    9/7=-(1/6)(-6)+c

    So what's c?

    So now we have the equation of the line, we need the value of the point on that line where x=12. Plug in 12 instead of x in the equation and work out what y must be.


    18y+2x-9=0
    we need to write as y=mx+c
    18y+2x-9=0
    move everything but y to the RHS:
    18y=-2x+9
    y=(-2/18)x+9/18
    which you can simplify a bit.

    You can do the other yourself the same way.

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