# algebra

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Find the value of y so that the line passing through the two points has the given slope?
1. (12,y), (-6,9/7), m= -1/6
_____________

write an equation in slope-intercept form. (then graph the equation).
2. 18y+2x-9=0
3. 3x-4y=-8

• algebra -

y=mx+c
m= -1/6
y=-(1/6)x+c
The point (-6,9/7) must be on that line: use it to find c by plugging in x and y like
9/7=-(1/6)(-6)+c

So what's c?

So now we have the equation of the line, we need the value of the point on that line where x=12. Plug in 12 instead of x in the equation and work out what y must be.

18y+2x-9=0
we need to write as y=mx+c
18y+2x-9=0
move everything but y to the RHS:
18y=-2x+9
y=(-2/18)x+9/18
which you can simplify a bit.

You can do the other yourself the same way.

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