A 24.0 kg box (m1) rests on a table.(b) A 13.0 kg box (m2) is placed on top of the 24.0 kg box, as shown in Fig. 4-35.

Determine the normal force that the table exerts on the 24.0 kg box.
Determine the normal force that the 24.0 kg box exerts on the 13.0 kg box.

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To determine the normal force that the table exerts on the 24.0 kg box, we need to analyze the forces acting on the box. In this case, there are two forces acting on the box: the gravitational force (mg) pulling it downwards and the normal force (N) exerted by the table pushing it upwards.

To determine the normal force, we can use Newton's second law, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, since the box is not accelerating vertically, the net force must be zero.

Therefore, we can set up the following equation:
N - mg = 0

Simplifying the equation:
N = mg

Now we can substitute the given values into the equation:
N = (24.0 kg) * (9.8 m/s^2) = 235.2 N

So, the normal force that the table exerts on the 24.0 kg box is 235.2 N.

To determine the normal force that the 24.0 kg box exerts on the 13.0 kg box, we need to consider the forces acting on the 13.0 kg box. Again, there are two forces acting on the box: the gravitational force (mg) pulling it downwards and the normal force (N) exerted by the 24.0 kg box pushing it upwards.

Since the 13.0 kg box is not accelerating vertically, the net force acting on it must be zero. Therefore, we can set up the following equation:
N - mg = 0

Simplifying the equation:
N = mg

Substituting the given values:
N = (13.0 kg) * (9.8 m/s^2) = 127.4 N

So, the normal force that the 24.0 kg box exerts on the 13.0 kg box is 127.4 N.