Algebra
posted by Katie .
I have to figure out how x^3+216=0 is factored, and what potential solutions might be. I factored it like this: (x+3)(x+3)(x+24), resulting in the solutions being 3 (double route) and 24. But my book says these are not correct answers. Why not? Can you show me how to do it the right way? Thanks!

Use
A³+;B³=(A+B)(A²AB+B²)
A³;B³=(AB)(A²+AB+B²)
and note that 216=6³
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