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graph the equation and find the y-intercept.


My question is do I add -5x to both sides first?? how do I start this problem?

  • algebra -

    When you have an equation with just x and y terms, you're looking at a straight line.

    One way to approach is it, as you say, to add -5 to both sides, and then divide across by 2, so that the LHS just contains y on its own. Then you have it in the form y = mx + c, and you can just read off the y-intercept as c.

    Another way to find the y-intercept is to set x=0, and see what you're left with:

    2y+0 = -6

    So the point (0,-3) is on the line, and is the y-intercept.

    You also want to graph it. Since it's a straight line, you just need two points, then draw the line with a ruler.
    Let's get the x-intercept as our other point:


    So (-6/5,0) is tyhe x-intercept, and the second point we need for drawing the line.

  • algebra -

    Oops, typo. In case you're confused, I meant "One way to approach it is, as you say, to add -5x to both sides..."

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