Algebra
posted by confused .
Find the equation of the ellipse with vertices at (1,3) and (5,3)and length of minor 4.

first find the centre, which would be the midpoint of the vertices,
it would be (2,3)
the length of the minor axis is 4, so b = 2
sofar we would would have
(x2)^2/a^2 + (y3)^2/4 = 1
but (5,3) lies on it, so
(52)^2/a^2 + (33)^2/4 = 1
9/a^2 = 1
a^2 = 9
final equation
(x2)^2/9 + (y3)^2/4 = 1 
thanks!

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