The length of a rectangle is twice the width. The area is 18yrd squared. Find the lenght and the width.
L = 2W
Length times width = area.
L * W = 18
2W * W = 18
Solve for W, then put value in first equation to find L.
lenght=3.35 and width=1.37
To find the length and width of a rectangle, given the relation between the length and width, we can set up an equation using the given information.
Let's denote the width of the rectangle as "x". According to the given information, the length is twice the width, so the length can be represented as "2x".
The formula for the area of a rectangle is length multiplied by width: Area = Length * Width.
Given that the area is 18 square yards, we can set up the equation as follows:
18 = (2x) * x
Now, we need to solve this quadratic equation in order to find the value of x (width), and then use that value to calculate the length.
First, simplify the equation by multiplying:
18 = 2x^2
Divide both sides of the equation by 2:
9 = x^2
Next, take the square root of both sides of the equation to isolate x:
√9 = √x^2
3 = x
Now we know the width of the rectangle is 3 yards. To find the length, which is twice the width, we can substitute the value of x back into the equation:
Length = 2x = 2 * 3 = 6
Therefore, the length of the rectangle is 6 yards and the width is 3 yards.