In outer space, a constat net force of magnitude 140 N is exerted on a 32.5 kg probe initially at rest. (a) what acceleration does thie force produce? (b) how far does the probe travel in 10.0 s?

a= F/mass

d= 1/2a t^2= 1/2 F/m t^2

thanx

To find the acceleration produced by the force, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration (F = ma).

(a) Acceleration:
Given:
Net force (F) = 140 N
Mass of the probe (m) = 32.5 kg

Using the formula F = ma, we can rearrange it to solve for acceleration (a):
a = F/m

Substituting the given values, we have:
a = 140 N / 32.5 kg
a ≈ 4.31 m/s^2 (rounded to two decimal places)

Therefore, the acceleration produced by the force is approximately 4.31 m/s^2.

(b) Distance traveled:
To find the distance traveled by the probe in 10.0 s, you can use the equation of motion: distance (d) = initial velocity (v) * time (t) + 0.5 * acceleration (a) * time^2.

Given:
Initial velocity (v) = 0 m/s (since the probe is initially at rest)
Acceleration (a) = 4.31 m/s^2 (from part a)
Time (t) = 10.0 s

Using the formula, we have:
d = v * t + 0.5 * a * t^2
d = 0 * 10.0 + 0.5 * 4.31 * (10.0)^2
d ≈ 215.5 m (rounded to one decimal place)

Therefore, the probe will travel approximately 215.5 meters in 10.0 seconds.