I need some help with writing reactions. I have the following to write out:
a. the hydration of copper sulfate
b. the reaction of liquid sulfuric acid to form aqueous sulfuric acid
c. the reaction of calcium oxide w/ water to form calcium hydroxide
For a, I know copper sulfate is CuSO4+5H2O (after doing some research), I just don't know what's the reaction.
For b, I think the reaction would be just H2SO4(l) --> H2SO4 (aq), though I could be wrong.
And for c, isn't it CaO + H2O -->CaOH2?
Thank you!
There other hydrated copper sulfate.
CuSO4+ xH2O>>CuSO4.xH2O in your pentahydrate, x is 5.
H2SO4(l)+H2O>>H2SO4(aq)
On the last, the product is Ca(OH)2
For writing out reactions, it's important to understand the concept of balancing chemical equations. This involves making sure that the same number of atoms of each element is present on both sides of the equation.
a. The hydration of copper sulfate is the reaction where water molecules combine with copper sulfate to form a hydrated compound. The chemical equation can be written as:
CuSO4 + 5H2O → CuSO4 · 5H2O
In this reaction, water is added to copper sulfate to form copper sulfate pentahydrate, which is a blue crystalline solid.
b. The reaction of liquid sulfuric acid (H2SO4) to form aqueous sulfuric acid (H2SO4(aq)) does not involve any chemical change in the compound. Thus, the reaction can be simply represented as:
H2SO4(l) → H2SO4(aq)
In this case, the state symbol "(l)" indicates that the reactant is in the liquid state, while "(aq)" represents that the product is dissolved in water and exists as an aqueous solution.
c. The reaction of calcium oxide (CaO) with water (H2O) to form calcium hydroxide (Ca(OH)2) involves the addition of water to the oxide. The balanced chemical equation is:
CaO + H2O → Ca(OH)2
This reaction is an example of a base reacting with water to produce a hydroxide compound.
Remember, when in doubt, it's always helpful to consult reliable sources or textbooks to confirm the reactions and their balanced equations.