# math

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The Yankee Clipper leaves the pier at 9:00 am at 8 knots. A half hour later the River Rover leaves the same peir going in the same direction traveling at 10 knots. At what time will the River Rover overtake the Yankee Clipper?

• math -

Arithmetic:
Clipper's lead = 8 knots * (1/2) hour = 4 nautical miles
For each hour, the Rover catches up by (10-8)=2 nautical miles.
Time required to catch up = 4/2 hours (after 9:30)
Time the Rover will catch up = 11:30

Algebra:
Let t=time (as of 9:30) to catch up
10*t - 8*t = 8*(1/2)
2t = 4
t=2
The Rover will catch up at 11:30.

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