math
posted by Shayna .
The Yankee Clipper leaves the pier at 9:00 am at 8 knots. A half hour later the River Rover leaves the same peir going in the same direction traveling at 10 knots. At what time will the River Rover overtake the Yankee Clipper?
Please help me solve this using the d=rt formula and write an equation.

Arithmetic:
Clipper's lead = 8 knots * (1/2) hour = 4 nautical miles
For each hour, the Rover catches up by (108)=2 nautical miles.
Time required to catch up = 4/2 hours (after 9:30)
Time the Rover will catch up = 11:30
Algebra:
Let t=time (as of 9:30) to catch up
10*t  8*t = 8*(1/2)
2t = 4
t=2
The Rover will catch up at 11:30.
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