A house painter uses a chair and pulley arrangement to lift himself up the side of a house. The painter's mass is 69.2 kg and the chair's mass is 24.0 kg. With what force must he pull down on the rope in order to accelerate upward at 0.379 m/s2?

The rope that the painter pulls down on goes through a pulley and is attached the chair he is sitting on.

Since your trying to accelerate up you have to remember that g = -9.8. So to accelerate up you need to add 9.8 + .379, in order to find the acceleration. So it would be m = 93.2 and a = 10.179. Then solve for 2F = m*a. Answer is 474.34 N

I got 17.7 N as my answer, but it was incorrect. I'm not sure why.

Well, isn't this a "weighty" question! To find the force the painter must pull down on the rope, we can use Newton's second law of motion: F = ma.

First, let's find the total mass of the painter and the chair: 69.2 kg + 24.0 kg = 93.2 kg.

Now, we can calculate the force: F = (93.2 kg) x (0.379 m/s^2) = 35.3092 N.

So, the painter must pull down with a force of approximately 35.3092 N. But remember, don't pull too hard, or you might bring the whole house crashing down! Now that would be a real "paint"-ful situation!

To find the force the painter must exert on the rope, we can use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.

First, we need to calculate the total mass of the system, which is the sum of the painter's mass and the chair's mass:

Total mass = painter's mass + chair's mass
Total mass = 69.2 kg + 24.0 kg
Total mass = 93.2 kg

Now we can calculate the force the painter must exert:

Force = mass × acceleration
Force = 93.2 kg × 0.379 m/s^2
Force ≈ 35.3078 N

Therefore, the painter must pull down with a force of approximately 35.3078 Newtons on the rope in order to accelerate upward at 0.379 m/s^2.

The force F that the painter applies to the rope is doubled by the pulley so that 2F is what accelerates the painter and chair.

Solve the equation 2F = m a, where m is the total mass (69.2 + 24.0 kg). a is the acceleration, 0.379 m/s^2

The quantity you want is F