Three objects are connected as shown in the figure below. They move along a horizontal, frictionless surface, and are pulled to the right with a force Fext = 1.3 N. With the three mass values given as m1 = 726 g, m2 = 633 g, and m3 = 782 g. Calculate the magnitude of the acceleration of the three objects. thanks.
There is no "figure below" and you appear to be using different names for a series of questions of the same type. Show some work of your own if you expect additional assistance from me.
To calculate the magnitude of the acceleration of the three objects, we need to apply Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration: Fnet = ma.
In this case, the net force acting on the three objects is the external force pulling them to the right, which has a magnitude of Fext = 1.3 N.
However, in order to calculate the total mass of the three objects (m_total) and the acceleration (a), we need to consider that the force Fext is distributed among the three objects.
Let's start by calculating the total mass (m_total) of the three objects:
m_total = m1 + m2 + m3
m_total = 726 g + 633 g + 782 g
m_total = 2141 g
Next, we can use Newton's second law to find the magnitude of the acceleration (a):
Fnet = m_total * a
a = Fnet / m_total
Substituting the given force value:
a = 1.3 N / (2141 g)
Note: To convert grams to kilograms, divide by 1000 (1 kg = 1000 g).
a = 1.3 N / (2.141 kg)
a ≈ 0.606 m/s^2
So, the magnitude of the acceleration of the three objects is approximately 0.606 m/s^2.