This might sound a bit dumb but am really stuck :L
i need help to answer a question and i need someone to explain to me how to do it
Multiply out the brackets and collect the terms.
(2y-3)(ysqaured + 4y -1)
Multiply the stuff in the second set of parentheses by 2y to obtain:
y^2*2y + 4y*2y -1*2y = 2y^3+8y-2y
Then multiply the same stuff by -3 as I did above, and collect terms.
Not a problem at all! I'll help you out with that.
To multiply out the brackets and collect the terms, we need to apply the distributive property. This means we multiply each term from the first bracket with every term from the second bracket.
Let's break it down step by step:
Step 1: Multiply the first term of the first bracket with every term of the second bracket:
(2y) * ysquared = 2y * ysquared = 2y * (y^2) = 2y^3
(2y) * 4y = 2y * 4y = 8y^2
(2y) * (-1) = 2y * (-1) = -2y
Step 2: Multiply the second term of the first bracket with every term of the second bracket:
(-3) * ysquared = -3 * ysquared = -3 * (y^2) = -3y^2
(-3) * 4y = -3 * 4y = -12y
(-3) * (-1) = -3 * (-1) = 3
Step 3: Combine all the terms we obtained in Steps 1 and 2:
2y^3 + 8y^2 - 2y - 3y^2 - 12y + 3
Step 4: Simplify the expression by combining like terms:
2y^3 + (8y^2 - 3y^2) + (-2y - 12y) + 3
This gives us the final answer:
2y^3 + 5y^2 - 14y + 3
So, when you multiply out the brackets and collect the terms, the expression (2y-3)(ysquared + 4y -1) simplifies to 2y^3 + 5y^2 - 14y + 3.
I hope this explanation was clear and helped you understand the process! Let me know if you have any further questions.