algebra 1
posted by spirit73 .
the perimeter of a rectangle is 224 incles. the length exceeds the width by 64 inces. find the length and the width.
the length is _____ inches
and
the width is _____ inches

Let
L=length
W=width = L64
Perimeter = 224 = 2(L+W) = 2(L+L64)
Solve for L. 
A=1/2h(b1+b2)
solve for b 
"A=1/2h(b1+b2)
solve for b"
I do not see the variable b in the expression: b1 and b2 are different variables than b.
In any case, I suggest you start a new thread for a new question.