A light bulb, after it has reached its operation temperature, is connected across a potential difference of 120V while 0.5A of current passses through it. What is the resistance of the light bulb?
E = IR
120 = 0.5R
Solve for R.
120/0.5 = 0.5R/0.5
= 240 ohms
To find the resistance of the light bulb, we can use Ohm's Law, which states that the resistance (R) of a device is equal to the voltage (V) across it divided by the current (I) passing through it.
The given potential difference across the light bulb is 120V, and the current passing through it is 0.5A.
Using the formula: R = V / I
Substituting the given values: R = 120V / 0.5A
Calculating the result: R = 240 ohms
Therefore, the resistance of the light bulb is 240 ohms.
To find the resistance of the light bulb, you can make use of Ohm's Law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I).
Mathematically, it can be written as:
R = V / I
Given:
Potential difference (V) = 120V
Current (I) = 0.5A
Plugging the values into the formula, we get:
R = 120V / 0.5A
Performing the division, we find:
R = 240Ω
Therefore, the resistance of the light bulb is 240 ohms.