Chemistry II

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Acetone, C3H6O, is the main ingredient of nail polish remover. A solution is made up by adding 35.0mL of acetone(d=0.790g/mL) to 50.0mL of ethyl alcohol,C2H6O(d=0.798 g/mL). Assume that the volumes are additive. From this information calculate the molarity of acetone in the solution.
Ok is the mole of C3H6O 58.09mol, and if so, what do I do next?

  • Chemistry II -

    The molar mass of acetone is correct.
    Here is what you do.
    Convert density acetone and density ethyl alcohol (together with volume) to grams,
    density = mass x volume.
    mass = density/volume. You are given the density of each and the volume of each. Determine mass of each.

    Next, convert grams of each to moles.
    moles = grams/molar mass.

    Then molarity = moles/L and L = 50 mL + 35 mL = 85 mL = 0.085 L.

  • Chemistry II -

    If you do everything I suggested, you will do more than necessary. I just worked the problem. You don't need the mass of ethyl alcohol nor the moles ethyl alcohol.

  • Chemistry II -

    correction to the formula of density. density is equal to the ratio mass and volume, that is

    d=m/v
    m=d*v

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