CHEMISTRY

posted by .

Hydrogen cyanide, HCN, can be made by a two-step process. First, ammonia is reacted with O2 to give nitric oxide, NO.

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)
Then nitric oxide is reacted with methane, CH4.

2 NO(g) + 2 CH4(g) → 2 HCN(g) + 2 H2O(g) + H2(g)
When 28.6 g of ammonia and 25.1 g of methane are used, how many grams of hydrogen cyanide can be produced?

• CHEMISTRY -

This is a limiting reagent type problem. All of them can be worked in the following way.
1. Write and balance the equation. You have that.
2a. Convert 28.6 g NH3 to moles. Moles = grams/molar mass.
2b. Convert 25.1 g CH4 to moles.

3a. Using the coefficients in the balanced equation, convert moles NH3 to moles HCN.
3b. Using the coefficients in the balanced equation, convert moles CH4 to moles HCN.
3c. Obviously, one of the answers (either 3a or 3b) must be wrong. The smaller one is ALWAYS the correct value to use and the reagent that produced that value is the limiting reagent.

4. Using the smaller value from 3c, convert moles of HCN to grams. grams = moles x molar mass.
Post your work if you get stuck.

• CHEMISTRY -

I don't understand 3a and 3b. I don't understand how you do that

• CHEMISTRY -

OK. For 2a and 2b, we have the following but I have just used round numbers for the molar masses. You may want to redo them with more exact values.
28.6/17 = 1.68 moles NH3.
25.1/16 = 1.57 moles CH4.

I have led you astray a little. The NH3 must be converted to NO first. So we want to convert 1.68 moles NH3 to moles NO. Same directions.
3a.
moles NO = 1.68 moles NH3 x (4 moles NO/4 moles NH3) = 1.68 x (4/4) = 1.68 x 1/1 = 1.68 moles NO.[Note that the unit moles NH3 cancel and converts moles NH3 to moles NO. Now we convert moles NO to moles HCN.
moles HCN = 1.68 moles NO x (2 moles HCN/2 moles NO) = 1.68 x (2/2) = 1.68 x 1/1 = 1.68 moles HCN.

3b. Convert moles CH4 to moles HCN.
moles HCN = 1.57 moles CH4 x (2 moles HCN/2 moles CH4) = 1.57 x (2/2) = 1.57 x (1/1) = 1.57 moles HCN.

3c. The smaller number rules so CH4 is the limiting reagent and 1.57 moles HCN will be produced.

4. Now we convert 1.57 moles HCN to grams.
1.57 moles HCN x molar mass HCN = grams HCN.

Sorry about the mixup. I hope this is clear. If not, I think it would be better to start a new post at the top of the page, recopy the problem and post additional questions.

• CHEMISTRY -

the answer is shut up. muahahahaha

• CHEMISTRY -

sally is a big poo headed jerk face. she is sitting beside me drinking cranberry juice and just being a jerk. it's an everyday thing for her. you have to understand one thing... she's a playstation girl.... enough said.

• CHEMISTRY -

for one thing it is cran-grape, mister. secondly, playstation kills xbox. the end :) oh and i'm the nicest girl ever. i mean, come on, my name is sally :D

• CHEMISTRY -

cran-grape, shmamgrape... it all taste like poooooooooop. and yea ok miss i play a ps2. GET IN THE 21st CENTURY!!! and actually sally means baby eating booger flicker sooo ummm.... no. and o yea, your mac sucks..

• CHEMISTRY -

pc's suck :)

• CHEMISTRY -

When you react hydrogen gas with nitrogen gas to form ammonia, How many grams of all species ( reactants and products) are left when you start with 140 grams of nitrogen and 40 grams of hydrogen?

• CHEMISTRY -

Calculate the mass of water produced by 64 grams of CH4

CH4(G) - 2O2 (G) -----CO2(G)-2H2O(l)

• CHEMISTRY -

27gram

• CHEMISTRY -

Well for both of you crappy console lovers... PC GAMING IS SUPREME TO CONSOLE GAMING. ONE WORD... CUSTOMIZATION!

Similar Questions

1. Chemistry

Nitric Acid is produced from nitric oxide, NO which in turn is prepared from ammonia by the ostwald process. 4NH3 + 5O2 -----> 4NO + 6H2O What volume of oxygen at 35 degrees C and 2.15 atm is neeeded to produce 50.0 g of nitric …
2. Chemistry

with a platinum catalyst, ammonia will burn in oxygen to gove nitric oxide NO. What is the enthalpy change for the following reaction?
3. stoichiometry

Hydrogen cyanide is produced industrially from the reaction of gaseous ammonia, oxygen, and methane. 2 NH3(g) + 3 O2(g) + 2 CH4(g) ¨ 2 HCN(g) + 6 H2O(g) If 5.27 103 kg each of NH3, O2, and CH4 are reacted, what mass of H2O will …
4. Chemistry

With a platinum catalyst, ammonia will burn in oxygen to give nitric oxide, NO. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) ÄH = -906 kJ What is the enthalpy change for the following reaction?
5. chemistry

Hydrogen cyanide is produced industrially from the reaction of gaseous ammonia, oxygen, and methane. 2 NH3(g) + 3 O2(g) + 2 CH4(g) 2 HCN(g) + 6 H2O(g) If 5.00 x 10^3 kg each of NH3, O2, and CH4 are reacted, what mass of HCN and of …
6. Chemistry

In the first step of the Ostwald process for the synthesis of nitric acid, ammonia is converted to nitric oxide by the high-temperature reaction:4NH3(g)+5O2(g)+6H2O(g). How is the rate of consumption of O2 related to the rate of consumption …
7. chemistry

Hydrogen cyanide, HCN, can be made by a two-step process. First, ammonia is reacted with O2 to give nitric oxide, NO. 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) Then nitric oxide is reacted with methane, CH4. 2 NO(g) + 2 CH4(g) …
8. chemistry

Hydrogen cyanide, HCN, can be made by a two-step process. First, ammonia is reacted with O2 to give nitric oxide, NO. 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) Then nitric oxide is reacted with methane, CH4. 2 NO(g) + 2 CH4(g) …
9. Chemistry

The iodide ion can be oxidized in an acidic solution by hydrogen peroxide. One proposed mechanism for the reaction is as follows: Step 1: H2O2 (aq) + I-(aq) → H2O (l) + OI-(aq) slow Step 2: H+(aq) + OI-(aq) → HOI(aq) fast …
10. Chemistry ASAP

3. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4 + NH3 + O2  HCN + H2O You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer …

More Similar Questions