A calculator requires a keystroke assembly and a logic circuit. Assume that 83% of the keystroke
assemblies and 92% of the logic circuits are satisfactory. Find the probability that a finished
calculator will be satisfactory. Assume independence of keystroke assemblies and logic circuits.
since the events are independent, my thinking would be
(.83)(.92) = ...
To find the probability that a finished calculator will be satisfactory, we need to calculate the probability that both the keystroke assembly and the logic circuit are satisfactory.
Given:
- The probability of a keystroke assembly being satisfactory is 83% or 0.83.
- The probability of a logic circuit being satisfactory is 92% or 0.92.
- We assume independence between keystroke assemblies and logic circuits.
To find the probability of both events occurring, we multiply the probabilities together.
Probability of keystroke assembly being satisfactory = 0.83
Probability of logic circuit being satisfactory = 0.92
Probability of both events occurring = Probability of keystroke assembly being satisfactory * Probability of logic circuit being satisfactory
= 0.83 * 0.92
= 0.7636
Therefore, the probability that a finished calculator will be satisfactory is approximately 0.7636 or 76.36%.