Algebra

posted by .

[2x-12]/[3x-6] * [x^2-4]/[x^2-36] * [3x+18]/[4x+8]

Would the solution be (x-4) over 2(x-2)(x+2)?

  • Algebra -

    You seem to have written (x^2 - 4) as (x-4) at some point.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. algebra 1 help

    6(-3-2)^2 over -3^2-2(-3)(2)+2^2 6(-3-2)^2 over -3^2-2(-3)(2)+2^2 6(-5)^2 over -9+12+4 6(-5)^2 over 3+4 6(25)^2 over 7 6x150 over 7 900 over 7 am i correct with this can i go any further . 6(-3-2)^2 over -3^2-2(-3)(2)+2^2 6(-3-2)^2 …
  2. Algebra 2

    would some one please check these for me 1. divide x^2-36y^2 over 5x^2+30y divide (x^2-6xy) A: x+6y over (5x)(x^2+6y) 2. Add. Express your answer in simplest form. 2x 0ver x^2+15x+54 + 4over x+6 A: 6 over x+9 3. solve: (9 over x-5) …
  3. Algebra

    (x-3)/5 = (x-3)/x The x-3 is over the 5 and the other x-3 is over the x... I know to cross multiply so I would get 5(x-3)= x(x-3) But then would i just divide (x-3) by both sides?
  4. Algebra

    x^2-25 over x^2+7x, divided by x^2+7x+10 over x^2+9x+14. I found the solution to be x-5 over x, is this correct?
  5. Algebra

    m+3 over 3m, divided by 6m over m+3 Would the solution be 1 over 18m?
  6. Algebra

    x^3-x^2y over x^2-y^2, divided by x^3y over xy^2+y^3 My solution: y over x Am I right?
  7. Algebra

    x^3-36x over x^2+7x+6, divided by 6x^2-x^3 over x^2+x I know the right answer is -1, but I can't seem to get to it. I've gotten as far as [x(x-6)]/1] * 1/[x^2(6-x)], which is then equal to [x(x-6)]/x^2(6-x). And then would I reduce …
  8. alGEBRA 2 help please would appreciate

    x over (x+3) -x over(x-3)=x^2+9 over X^2-9 solve for x and check answer
  9. aLGEBRA 2 help please would appreciate

    X over X+3 subtract X over X-3 = X^2 + 9 over X^2 -9 solve for x. show all work thank you
  10. aLGEBRA 2 help please would appreciate

    X over X+3 subtract X over X-3 = X^2 + 9 over X^2 -9 solve for x. show all work thank you

More Similar Questions