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I donot understand how to do this practice question for a test I have tomorrow. can someone please show me step by step? (-> is an arrow)

lim x-> 0 (32-32cosx)/64

  • math -

    Step 1 in any limit question is to actually substitute the approach value into the expression.
    If you get a real number as an answer, that is it, you are done

    so lim (32-32cosx)/64 as x --> 0
    = (32-32(1))/64 = 0

    end of question.

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