Isotonic saline and is often given to patients intravenously to replenish lost fluids. Isotonic saline is a 0.9% 9G/100ml) solution of salty water. You are asked to make up 21 of isotonic saline. How much salt should you weigh out?
21 what? mL, liters, gallons, water tanks?
Also, 0.9% would mean 0.9 g/100 wouldn't it?
2.25
To calculate the amount of salt needed to make 21 liters of isotonic saline solution, we need to determine the concentration of salt in the solution.
Isotonic saline is defined as a 0.9% (9g/100ml) solution. This means that in every 100 ml of the solution, there are 9 grams of salt.
To find the amount of salt needed for 21 liters of solution, we can use the following steps:
Step 1: Convert liters to milliliters.
21 liters x 1000 ml/liter = 21,000 ml
Step 2: Calculate the amount of salt needed for the given volume.
9 grams of salt / 100 ml = x grams of salt / 21,000 ml
To solve for x, we can set up a proportion:
9 grams / 100 ml = x grams / 21,000 ml
Cross-multiply:
(9 grams)(21,000 ml) = (100 ml)(x grams)
189,000 grams ml = 100 ml x grams
Step 3: Simplify the equation and solve for x.
189,000 grams ml / 100 ml = x grams
x = 1890 grams
Therefore, you would need to weigh out 1890 grams of salt to make 21 liters of isotonic saline solution.