Trista has 8 coins in her pocket that total to $1.55.She only has quarters
and dimes.How many of each coin does
Trista have?
let the number of quarters be x
then the number of dimes is 8-x
25x + 10(8-x) = 155
take it from there
3 qaurters and and 8 dimes
your mom
oops sorry I forgot all about the 8 coins
She has 3 quarters and 5 dimes
bro tbhh idkk
To solve this problem, we can use a system of equations.
Let's represent the number of quarters that Trista has as "q" and the number of dimes as "d".
Since Trista has a total of 8 coins, we can write the equation:
q + d = 8 -- Equation 1
Since the value of a quarter is $0.25 and the value of a dime is $0.10, we can write the equation for the total value of the coins:
0.25q + 0.10d = 1.55 -- Equation 2
We now have a system of two equations with two variables. We can solve this system to find the values of "q" and "d".
To solve the system, we can use the method of substitution or elimination. Let's use the method of substitution for this example.
From Equation 1, we have:
q = 8 - d
Substituting this into Equation 2, we get:
0.25(8 - d) + 0.10d = 1.55
Expanding the equation, we have:
2 - 0.25d + 0.10d = 1.55
Combining like terms, we get:
0.85d = 1.55 - 2
Simplifying further, we have:
0.85d = -0.45
Dividing both sides by 0.85, we get:
d = -0.45 / 0.85
d ≈ -0.5294
The value of "d" cannot be negative since we can't have a negative number of dimes. Therefore, there is an error in the problem or the information given.
Please check the information again or provide additional details if you meant something else.