posted by Willie .
A hiker throws a ball at an angle of 21.0 degrees above the horizontal from a hill 21.0 m high. The hiker's height is 1.750 m. The magnitudes of the horizontal and vertical components of the velocity are 14.004 m/s and 5.376 m/s, respectively. Find the distance between the base of the hill and the point where the ball hits the ground.(Consider the hiker's height while calculating the answer.)
Consider only the vertical component (5.376 m/s).
Calculate the time it takes to hit the ground below after reaching a maximum height in the air, since the ball is thrown upwards.
If we can ignore air resistance, the horizontal distance is the product of the horizontal component of initial velocity and the time to reach the ground.