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How many moles of excess reactant are present when 3.50 x 10^2 mL of 0.216 M sulfuric acid reacts with 0.510 L of 0.202 M sodium hydroxide to form water and aqueous sodium sulfate?

  • chemistry -

    Moles H2SO4 = M x L
    moles NaOH = M x L
    2NaOH + H2SO4 ==> Na2SO4 + 2H2O
    moles NaOH = 2 x moles H2SO4
    Excess = larger - smaller.
    Post your work if you need additional help.

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