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trig please

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I have no idea how to do this

Find the value of the angle theta in degrees rounded to the neartest tenth of a degree.

I have no idea were to start...

h t t p : / / i m g 6 . i m a g e s h a c k . u s / i m g 6 / 5 8 9 9 / a d s f a s d f a s d f a d s f s a d f . j p g

  • trig please -

    the circles go to the top and there measurements i included in the pictures and there are right angles

  • Please -

    if you don\'t understand the problem i tried to draw it in paint

  • trig please -

    Are you sure the 2 circles don't touch ?

    If the do, it is an easy problem.
    draw a line from the vertex through the two centres.
    Let the distance between the vertex and the centre of the smaller circle be x
    then the distance from the vertex to the centre of the larger circle is x+6

    sin (theta/2) = 2/x
    sin (theta/2) = 4/(x+6)
    then 2/x = 4/(x+6)
    which solves for x=6

    then sin (theta/2) = 2/6
    theta/2 = 19.47º
    theta = 38.942º or 38.9º to the nearest tenth.

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