What si the molar mass of Pb3(PO4)2 in units of g/mol?
Look up the atomic masses of Pb, P, and O
Multiply the atomic mass of Pb by 3.
Multiply the atomic mass of P by 2.
Multiply the atomic mass of O by 8.
Add the three values you got. That is the formula mass which you label "grams/mole".
Ah, Pb3(PO4)2, or as I like to call it, the "molar mass merriment." Let's break it down!
First, we have Pb, which stands for "Plumbum" because apparently, lead needed a fancy ancient name. The atomic mass of Pb is approximately 207.2 g/mol.
Next up, we have PO4. Phosphate, as it prefers to be called, is like the diva of the molecule world. It consists of 1 phosphorus (P) atom and 4 oxygen (O) atoms. The atomic mass of P is approximately 31 g/mol, and each oxygen atom weighs around 16 g/mol. So, when we add them all together, we get (31 + 4 * 16) = 95 g/mol for PO4.
Now, since we have 3 Pb atoms and 2 (PO4) groups, we can sum it up like this:
(3 * 207.2) + (2 * 95) = 621.6 + 190 = 811.6 g/mol.
So, the molar mass of Pb3(PO4)2 is approximately 811.6 g/mol. Don't forget to carry around the atomic humor!
To find the molar mass of Pb3(PO4)2, we need to calculate the sum of the atomic masses of all the elements in the compound.
The atomic masses are as follows:
- Pb (Lead): 207.2 g/mol
- P (Phosphorus): 30.97 g/mol
- O (Oxygen): 16.00 g/mol
First, let's calculate the molar mass of the phosphate ion (PO4):
Molar mass of P = 30.97 g/mol
Molar mass of O = 16.00 g/mol
Total molar mass of PO4 = (30.97 g/mol) + 4 × (16.00 g/mol) = 94.97 g/mol
Next, let's calculate the molar mass of Pb3(PO4)2:
Molar mass of Pb3(PO4)2 = 3 × (207.2 g/mol) + 2 × (94.97 g/mol)
= 621.6 g/mol + 189.94 g/mol
= 811.54 g/mol
Therefore, the molar mass of Pb3(PO4)2 is 811.54 g/mol.
To find the molar mass of Pb3(PO4)2, we need to calculate the sum of the atomic masses of each element in the compound.
First, let's break down the compound into its individual elements:
- Pb: This stands for lead
- P: This stands for phosphorus
- O: This stands for oxygen
Now, let's find the atomic masses of each element using the periodic table:
- Pb (lead) has an atomic mass of 207.2 g/mol
- P (phosphorus) has an atomic mass of 30.97 g/mol
- O (oxygen) has an atomic mass of 16.00 g/mol
Next, let's count how many of each element we have in the compound:
- Pb3(PO4)2 tells us there are three lead atoms (Pb3), two phosphate ions (PO4) and two oxygen atoms per phosphate (2 x O).
Now let's calculate the molar mass:
- For the lead (Pb3), we multiply the atomic mass of Pb (207.2 g/mol) by 3 (the coefficient), giving us a total of 621.6 g/mol.
- For the phosphate ion (PO4), we add the individual atomic masses of the elements: P (30.97 g/mol) + O (16.00 g/mol) x 4 (there are four oxygen atoms in each phosphate ion), giving us a total of 94.97 g/mol.
- Finally, we multiply the molar mass of the phosphate ion (94.97 g/mol) by 2, since there are two phosphate ions in the compound.
Summing it all up, the molar mass of Pb3(PO4)2 is:
621.6 g/mol (lead) + (94.97 g/mol x 2) (phosphate ions) = 811.54 g/mol
Therefore, the molar mass of Pb3(PO4)2 is approximately 811.54 g/mol.