Trig Picture

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maybe i drew it wrong...

h t t p : / / i 3 2 . t i n y p i c . c o m / i p m k o 5 . j p g

the way my teacher taught me the angle of depression was the anlge that is made with a horizontal line or something like that

i believed i drew it right

oh and by the way this is the diagram i drew for that problem i asked earlier which I\'m not sure to do i though it drew it right

  • Trig Picture -

    Here's the link to the diagram.

  • Trig Picture -

    The angle PAQ is the angle of elevation viewed from the ship, which is the same as the angle of depression viewed from the airplane (8°20'). The same for ship B.

    This is because the angles of elevation and depression are alternate angles between two parallel lines.

    I agree with the two calculations above using H/tan(θ) for the horizontal distance, and the answer of 13.143 km.

    See original post:

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