1.eleven applications for a certain position had the following ages. 32, 33, 25, 36, 48, 51, 28, 23, 54, 52, 45. sort them out in ascending order. 23, 25, 32, 33, 36, 45, 48, 51, 54, I picked 33 for the middle number to get the median is it correct?
2.clay is building a pen for his dog. he plans to make it rectangular in shape & measuring 40ft. by 50ft.. he can buy fencing fro $3.75 per ft. how much will the fencing for his dog pen cost? $675.00 2 (40+50)=180ft. 180ft* 375= $675.00 is this correct?
3.find the mode of the following set of answers 11, 10, 6, 11, 12= 11 mode is this correct?
thank you
1.
Your sorted list contains only 9 of the 11 numbers, so 33 is not correct.
If you use the complete sorted list of 11 numbers, I am sure you'll get it right. You're getting there.
2. $675 is correct.
3. 11 is correct. It is the most occurring value.
1. You only arranged 9 of the 11 in ascending order -- so your median is wrong.
2. Correct
3. Correct
1. To sort the ages in ascending order, you can arrange them from smallest to largest. Here is the sorted list: 23, 25, 28, 32, 33, 36, 45, 48, 51, 54. However, your pick of 33 for the middle number is incorrect. The median is the middle value when the data set is arranged in ascending order. In this case, the median is 36 because it is the value that separates the lower and upper halves of the data set.
2. To calculate the cost of the fencing for the dog pen, you need to find the perimeter of the rectangular shape. Since the length is 40ft and the width is 50ft, the perimeter can be found by adding the lengths of all four sides: 40 + 40 + 50 + 50 = 180ft. Then, you multiply the perimeter by the cost per foot of fencing, which is $3.75. So, 180ft * $3.75 = $675. Hence, your calculation is correct.
3. The mode refers to the value(s) that appear most frequently in a data set. In this case, the answers are 11, 10, 6, 11, and 12. The number 11 appears twice, while the other numbers appear only once. Therefore, the mode is 11. Your answer is correct.
You're welcome! If you have any more questions, feel free to ask.