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A solution is prepared by dissolving 10.0 moles of Na2SO4 solid in 0.500 kg H2O. what is the vapor pressure of the solution at 30 C?

  • Chemistry -

    *10 moles of Na2SO4 is 3*10=30 moles of particles.
    *Convert 0.500 kg H2O to moles.
    *Total moles = 30 + moles of H2O
    *Mole fraction of H2O = X(H2O) = (moles H2O) / Total moles.
    *Look up the vapor pressure of H2O at 30ºC = P(H2O)
    *Vapor pressure of solution = [X(H2O)]*[P(H2O)]

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