The equation of the line that goes through the points ( -9 ,-6 ) and ( -6 ,-3 ) can be written in general form A x + B y + C = 0 where B=?
I don't see that this can be determined with only two points. You have three unknowns.
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http://www.jiskha.com/display.cgi?id=1251678543
first find the slope
slope = (-3+6)/(-6+9) = 1
So the equation must have form
x - y + C = 0
sub in either point, I pick (-6,-3)
-6 + 3 + C = 0
C = 3
so the equation is x - y + 3 = 0
looks like B = -1
homework sheet
To find the equation of the line that goes through the points (-9, -6) and (-6, -3) in the general form A x + B y + C = 0, we need to find the values of A, B, and C.
First, we need to find the slope of the line using the formula:
slope (m) = (change in y) / (change in x)
Using the two points (-9, -6) and (-6, -3), we have:
change in x = -6 - (-9) = -6 + 9 = 3
change in y = -3 - (-6) = -3 + 6 = 3
slope (m) = (3) / (3) = 1
Now that we have the slope (m = 1), we can use the point-slope formula to find the equation of the line:
y - y₁ = m(x - x₁)
where (x₁, y₁) is a point on the line and m is the slope.
Choosing the point (-9, -6) as our (x₁, y₁), we have:
y - (-6) = 1(x - (-9))
y + 6 = x + 9
Now we can rewrite this equation in the general form A x + B y + C = 0:
x - y - 3 = 0
Comparing this equation with A x + B y + C = 0, we can determine that B = -1.
Therefore, B = -1.