A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds. how 1. much did the hockey puck accelerat?

2. how much force was exerted on the puck?

3. how much force did the puck exert on the hockey stick?

To find the answers to these questions, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass. We can utilize the following equations:

1. Acceleration (a) can be calculated using the formula:
a = Δv / Δt
Here, Δv represents the change in velocity, and Δt represents the change in time. Given that the velocity change is 6 m/s and the time change is 2 seconds, we can substitute these values into the equation to find the acceleration.

2. Force (F) can be determined using the formula:
F = m * a
where m represents the mass of the object and a is the acceleration. By substituting the values of mass and acceleration, we can calculate the force exerted on the puck.

3. According to Newton's third law of motion, if a hockey puck exerts a force on the hockey stick, the stick exerts an equal and opposite force on the puck. Therefore, the force exerted by the puck on the hockey stick will be the same as the force exerted on the puck.

Let's calculate the answers step by step:

1. The acceleration can be calculated as:
a = Δv / Δt
a = 6 m/s / 2 s
a = 3 m/s²

Therefore, the puck accelerated at a rate of 3 m/s².

2. The force exerted on the puck can be calculated as:
F = m * a
F = 0.200 kg * 3 m/s²
F = 0.6 N

Therefore, the force exerted on the puck is 0.6 Newtons.

3. The force exerted by the puck on the hockey stick will be equal to the force exerted on the puck, which is 0.6 Newtons.

Thus, the answers to the questions are:

1. The hockey puck accelerated at a rate of 3 m/s².
2. The force exerted on the puck is 0.6 Newtons.
3. The force exerted by the puck on the hockey stick is also 0.6 Newtons.