Trig....

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use specific triangles and the unit circle to geth the values.
tan(5pi/6?)

  • Trig.... -

    5pi/6 or 150º has a reference angle of pi/6 or 30º

    So you are dealing with the 30,60,90º triangle, resulting in that triangle constructed in the second quadrant.
    In the second quadrant the tangent is negative, and since tan pi/6 = 1/√3

    tan (5pi/6) = -1/√3

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