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two airplanes leave an airport at the same time. the velocity of the first airplane is 700 m/h at a heading of 52.2degrees . the velocity of the second is 600 m/h at a heading of 97 degrees . how far apart are they after 3.1 h? answer in units of m.

  • physics -

    The angle between them is the difference of the two bearings, each has a leg of velocity*time

    Using the law of cosines...

    c^2=leg1^2 + leg2^2 -2*leg1*lleg2*cosC

    where angle C is the difference of headings.

  • physics -

    not sure if i calculated right but is 1562 m the right answer : /

  • physics -

    what were your legs,and the angle?

    I will check those.

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