Find the coordinates of the missing endpoint given that S is the midpoint of line RT.
T(-4,3), S(1-,5)
How do you work this out?
S(-4,-6) and S(-7,-3) find T
h55h
To find the missing endpoint of a line given that S is the midpoint of line RT, you can use the midpoint formula.
The midpoint formula states that the coordinates of the midpoint (S) between two endpoints (R and T) can be found by taking the average of the x-coordinates and the average of the y-coordinates of R and T.
In this case, we are given the coordinates of T as T(-4,3) and S as S(1,-5). Let's denote the coordinates of the missing endpoint as (x, y).
Using the midpoint formula, we can write the following equations:
x-coordinate of S = (x-coordinate of R + x-coordinate of T) / 2
1 = (-4 + x) / 2
Solving for x:
2 = -4 + x
x = 2 + 4
x = 6
y-coordinate of S = (y-coordinate of R + y-coordinate of T) / 2
-5 = (3 + y) / 2
Solving for y:
-5 = 3 + y
y = -5 - 3
y = -8
Therefore, the missing endpoint has coordinates (6, -8).
the the endpoint be R(a,b)
you should have learned that if (x1,y1) and (x2,y2) are any two points, then the midpoint is
((x1+x2)/2,(y1+y2)/2)
so (-4+a)/2 = 1
and (3+b)/2 = -5
solve the first equation for a, the second for b