Math
posted by Jeremy .
Find the quotient 3(cos (5pi/12) + i sin (5pi/12) / 6(cos (pi/12) i sin (pi/12)). Express the quotient in rectangular form.
I have no idea what I did but I got (1/4)  433i/1000.

Using the identity
cos(x)+i sin(x) = e^{ix}
the expression simplifies considerably:
3(cos (5pi/12) + i sin (5pi/12) / 6(cos (pi/12) + i sin (pi/12))
=3(e^{5iπ/12})/6(e^{iπ/12})
=(1/2)e^{(5iπiπ)/12}
=(1/2)e^{iπ/3}
=(1/2)(cos(π/3)+i sin(π/3))
=(1/2)(1/2+(√3/3)i)
=1/4+(√3/6)i
Note: the identity can be derived by the expansion of e^{ix}
=1 + ix + (ix)²/2! + (ix)³/3! + ...
=1 +ix x²/2!  x³/3! + ...
=1 x²/2! + x⁴/4!  x⁶/6! + ...
+ i( x  x³/3! + x⁵/5!  ...)
= cos(x) + i sin(x)
Alternatively, multiply both numerator and denominator by the conjugate of the denominator, namely (cos (pi/12) i sin (pi/12))
to reduce the denominator to:
6(cos (pi/12)+i sin (pi/12))(cos (pi/12)i sin (pi/12))
=6(cos²(π/12)+sin²(π/12))
=6
The numerator becomes
3(cos (5pi/12) + i sin (5pi/12)(cos (pi/12)i sin (pi/12))
=3(cos(5&pi/12)cos(&pi/12)+sin(5&pi/12)sin(&pi/12))
+ 3i(sin(5&pi/12)cos(&pi/12)cos(5π/12)sin(&pi/12))
=3(cos(&pi/3)+isin(&pi/3))
So the result is also
3(cos(&pi/3)+isin(&pi/3))/6
=(1/2)(1/2+(√3/3)i)
=1/4+(√3/6)i
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