Hi! I have a question
Heres the problem:
3-2[6-(4y-1)]
I got -8y-11 but it wasn't right and I don't know what i did wrong help please!
3 - 2[6 - (4y - 1)]
Start with the polynomial inside the bracket. Distribute the negative 1.
= 3 - 2[6 - 4y - (-1)]
= 3 - 2[6 - 4y + 1]
= 3 - 2[7 - 4y]
Now distribute the -2
= 3 - 2(12) - 2(-4y)
= 3 - 24 + 8y
= 8y - 21
Okay I got you up to the "Distribute the -2 then im confused...where did you get the 12 in 3-2(12)-2(-4y)?
I think it was a typo:
it should be
= 3 - 2(7) -2(-4y)
= 3 - 14 + 8y
= 8y - 11
Okay great that makes more since thanks
To solve the expression 3-2[6-(4y-1)], it's important to follow the order of operations, which is commonly remembered using the acronym PEMDAS.
P: Parentheses (simplify expressions inside parentheses first)
E: Exponents (perform any exponent calculations)
MD: Multiplication and Division (perform any multiplication and division operations from left to right)
AS: Addition and Subtraction (perform any addition and subtraction operations from left to right)
Let's break down the expression step by step:
1. Start with the innermost parentheses:
- Inside the parentheses, we have 4y - 1.
- So, 6 - (4y - 1) simplifies to 6 - 4y + 1.
2. Now, apply the multiplication operation:
- We have 2 multiplied by the expression 6 - 4y + 1.
- Multiplying 2 by each term inside the parentheses, we get:
2 * 6 - 2 * 4y + 2 * 1, which simplifies to 12 - 8y + 2.
3. Finally, apply the subtraction operation:
- We have the expression 3 minus the result of step 2: 12 - 8y + 2.
- Subtracting each term, we get: 3 - 12 + 8y - 2.
- Combining like terms, we have: -9 + 8y - 2.
- Further simplifying, we get: 8y - 11.
So, based on the calculation, the correct simplification of the expression 3-2[6-(4y-1)] is 8y - 11. It seems you made an error in the calculation.