I need to graph the following equation
y=x+7
and then identify the y-intercept
(which I think is the 7)?
Please guide me on this one...ty:)
The y intercept is 7, good job.
So you have one point - (0, 7) - the y intercept.
Now, graph another point so you can draw a line...any point will do really. For example, x=1, which gives a nice y value.
At x = 1, y = 1+7 = 8.
So your second point is (1, 8).
Plot those points, draw a line connecting them (the slope of y=x+7 is constant so the equation is completely linear) and extending infinitely in either direction (use arrows).
Thank you :)
Sure! I can guide you through graphing the equation y = x + 7 and identifying the y-intercept.
To graph the equation, you need to plot points on a coordinate grid. The equation is in the form of y = mx + b, where m is the slope and b is the y-intercept.
Start by picking a few values for x and finding the corresponding y values. Let's choose three values of x: -3, 0, and 3.
For x = -3:
y = -3 + 7
y = 4
So, one point on the graph is (-3, 4).
For x = 0:
y = 0 + 7
y = 7
Another point on the graph is (0, 7).
For x = 3:
y = 3 + 7
y = 10
A third point on the graph is (3, 10).
Plot these points on a coordinate grid. Draw a straight line through the points to represent the equation y = x + 7.
Now, to identify the y-intercept, you are correct! The y-intercept is the point where the graph intersects the y-axis. In this case, the y-intercept is (0, 7), where x = 0 and y = 7.
So, the graph of the equation y = x + 7 is a straight line that passes through the point (0, 7) and has a slope of 1.