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The value of cos^-1(-(sqrt3/2)) in degree measure is what?
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150 degrees? Check that.
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Find a polynomial function of degree 3 with the given numbers as zeros.
-5, sqrt3, -sqrt3 Would this work as a function for this
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Yes, this works. You may be expected to expand the terms to the standard polynomial form. Note that
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Find the exact solution(s) of the system: x^2/4-y^2=1 and x=y^2+1
A)(4,sqrt3),(4,-sqrt3),(-4,sqrt3),(-4,-sqrt3)
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I have to sketch such a problem to see what I am doing. x^2 /2^2 -y^2/1^2 = 1 is a hyperbola
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Using the exact trigonometric ratios of 45 degree,30 degree and 60 degree,evaluate the following,leaving where necessary your
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sin 30 = 1/2 thus, we get 3/2 - 2cos 60 cos 60 = 1/2 thus we get 3/2 - 2/2 = 1/2 tan45 = 1 so the
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Find the exact solution(s) of the system: x^2/4-y^2=1 and x=y^2+1
A)(4,sqrt3),(4,-sqrt3),(-4,sqrt3),(-4,-sqrt3)
Top answer:
To find the exact solutions of the given system of equations, we need to solve the two equations
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(sqrt3 + 5)(sqrt3 -3) ?
multiply that out sqrt3*sqrt3 -3sqrt3 +5sqrt3 -15 now combine and simplify terms. yes the problems is:
Top answer:
To simplify the expression ((sqrt3)+5)((sqrt3)-3), you can use the FOIL method. Replace the brackets
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The measure of Ø of an angle in standard position is given.
a. Write each degree measure in radians and each radian measure in
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It is not clear what angle measure is given. Please provide the angle measure in order to complete
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The measure of Ø of an angle in standard position is given.
a. Write each degree measure in radians and each radian measure in
Top answer:
a. 5π/6 radians ≈ 150° π/3 radians ≈ 60° g. cos(5π/6) = -1/2 sin(5π/6) = √3/2
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Find a polynomial function of degree 3 with the given numbers as zeros.
-5, sqrt3, -sqrt3
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(x+5)(x+sqrt3)(x-sqrt3) = 0 Multiplying out the left side gives you: (x+5)*(x^2-3) = 0 x^3
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Find a polynomial function of degree 3 with the given numbers as zeros.
-5, sqrt3, -sqrt3
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The general cubic with given roots r1,r2,r3 is given by: y=k(x-r1)(x-r2)(x-r3) where k is a
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Determine the measure of side a ( to the nearest degree and minute).
sin a = sin A cos B sin A = cos a cos B cos a = cos B/ sin A
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As \(\cos A = \frac{\cos a}{\sin B}\), \(\cos a = \cos A \cdot \frac{\sin B}{\cos B}\). Since
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